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Question 1
Incorrect
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Which B vitamin is part of fatty acid synthesis?
Your Answer: B6
Correct Answer: B5
Explanation:The B vitamin that is part of fatty acid synthesis is B5, also known as pantothenic acid. Pantothenic acid is an essential nutrient that is required for the synthesis and metabolism of fats, proteins, and carbohydrates. It plays a crucial role in the production of coenzyme A (CoA), which is necessary for the breakdown and utilization of fatty acids. Without sufficient levels of pantothenic acid, the body would not be able to efficiently synthesize fatty acids, leading to potential deficiencies and imbalances in lipid metabolism.
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This question is part of the following fields:
- Biochemistry
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Question 2
Correct
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What is the single best test to request in a patient suspected of hyperthyroidism?
Your Answer: TSH
Explanation:The single best test to request in a patient suspected of hyperthyroidism is the TSH (thyroid-stimulating hormone) test.Hyperthyroidism is a condition characterized by an overactive thyroid gland, which leads to excessive production and release of thyroid hormones. The most common cause of hyperthyroidism is Graves’ disease, an autoimmune disorder that stimulates the thyroid gland to produce excessive amounts of thyroid hormones.The TSH test is the most sensitive and specific test for diagnosing hyperthyroidism. TSH is a hormone produced by the pituitary gland in the brain, and its primary function is to stimulate the thyroid gland to produce and release thyroid hormones (T3 and T4). In cases of hyperthyroidism, the excessive production of thyroid hormones leads to a negative feedback loop, causing the pituitary gland to decrease its production of TSH.Therefore, in a patient suspected of hyperthyroidism, a low TSH level is indicative of an overactive thyroid gland and supports the diagnosis of hyperthyroidism. If the TSH level is low, further tests such as T3 and T4 levels may be requested to confirm the diagnosis and determine the severity of hyperthyroidism.Other tests such as T3 (triiodothyronine), T4 (thyroxine), and FT3 (free triiodothyronine) may also be useful in evaluating thyroid function, but the TSH test is the initial and most important test to request in the diagnostic workup of hyperthyroidism. Thyroglobulin and TSI (thyroid-stimulating immunoglobulin) are more specific tests used to differentiate between different causes of hyperthyroidism, such as Graves’ disease.
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This question is part of the following fields:
- Internal Medicine
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Question 3
Incorrect
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What is the recommended age for surgical repositioning of an undescended testis?
Your Answer: 24 months
Correct Answer: 6 months
Explanation:The recommended age for surgical repositioning of an undescended testis is typically before the child is 12 months old. This is because the testis should ideally descend into the scrotum by the time a baby boy reaches 6 months old. If the testis has not descended by this age, it is considered undescended or cryptorchid.Surgical repositioning, also known as orchidopexy, is usually recommended within the first year of life to prevent potential complications and improve fertility outcomes in the future. The earlier the surgery is performed, the better the chances of successful testicular descent and normal testicular development.There are several reasons why early surgical intervention is preferred. Firstly, the undescended testis is more prone to injury and trauma if it remains in the inguinal canal or abdomen. This can lead to testicular torsion, which is a painful condition where the testis twists on its own blood vessels, potentially cutting off its blood supply. Testicular torsion requires emergency surgery and can result in permanent damage to the testis if not treated promptly.Secondly, an undescended testis may have impaired fertility potential. The testis needs to be in the scrotum, which has a lower temperature than the abdomen, for optimal sperm production. If the testis remains undescended for an extended period, it may affect the production and quality of sperm, potentially leading to infertility issues later in life.Lastly, early surgical intervention allows for better monitoring and follow-up. After the surgery, regular check-ups can be scheduled to ensure proper testicular development and address any potential complications or concerns.It is important to note that the recommended age for surgical repositioning may vary depending on individual circumstances and the advice of a healthcare professional. Factors such as the severity of the undescended testis, the presence of other associated conditions, and the overall health of the child may influence the timing of the surgery. Therefore, it is crucial to consult with a pediatric urologist or surgeon who can provide personalized recommendations based on the specific case.
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This question is part of the following fields:
- Surgery
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Question 4
Incorrect
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What microscopic finding in the trophozoite is diagnostic of Entamoeba histolytica infection?
Your Answer: Charcot-Leyden crystal
Correct Answer: Ingested RBC
Explanation:The microscopic finding in the trophozoite that is diagnostic of Entamoeba histolytica infection is the presence of ingested red blood cells (RBCs). Entamoeba histolytica is a parasitic amoeba that causes amoebic dysentery, a severe form of diarrhea. When examining a stool sample under a microscope, the trophozoite stage of Entamoeba histolytica can be identified by its characteristic appearance and movement. One of the key features of this parasite is its ability to ingest and digest red blood cells. This can be observed as the presence of intact or partially digested RBCs within the cytoplasm of the trophozoite. This finding is specific to Entamoeba histolytica and helps differentiate it from other non-pathogenic amoebas or other causes of diarrhea.
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This question is part of the following fields:
- Microbiology
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Question 5
Correct
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For a child to be considered legitimate, must they be born within a lawful wedlock or within how many days after the dissolution of marriage?
Your Answer: 300 days
Explanation:The number of days after the dissolution of marriage for a child to be considered legitimate varies depending on the country or state.In the Philippines, a child is considered legitimate if they are born within 300 days after the dissolution of marriage. This is according to Article 145 of the Family Code of the Philippines.In the United States, the number of days after the dissolution of marriage for a child to be considered legitimate also varies depending on the state. In general, a child is considered legitimate if they are born within 300 days after the dissolution of marriage. However, there are some states that have shorter or longer periods of time.
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This question is part of the following fields:
- Legal Medicine And Juris
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Question 6
Incorrect
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In the above scenario, RP's right foot was noted to be cool, pale, with absent pulses, and a hematoma over the fracture site. Which of the following is not true in the management?
Your Answer: This would require operative exploration as absent pulses is a hard sign
Correct Answer: Due to the presence of nerve injury, observation is only warranted
Explanation:The statement that is not true in the management is due to the presence of nerve injury, observation is only warranted. This statement is incorrect because in the given scenario, RP’s right foot has absent pulses, which is a hard sign of vascular compromise. Absent pulses indicate a lack of blood flow to the foot, which can lead to tissue damage and potentially limb loss if not addressed promptly. Therefore, operative exploration is necessary to assess and potentially repair the vascular injury. Nerve injury, on the other hand, may also be present but does not negate the need for immediate vascular examination and intervention.
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This question is part of the following fields:
- Surgery
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Question 7
Incorrect
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What is achieved by giving a pseudomenopause state?
Your Answer: Clomiphene citrate 250 mg/day
Correct Answer: Danazol 400-800 mg/day for 6 months
Explanation:Pseudomenopause state can be achieved by giving certain medications or undergoing certain medical procedures. This state refers to a temporary cessation or suppression of menstrual cycles, similar to menopause. It is often used in medical treatments for conditions such as endometriosis, uterine fibroids, or certain types of cancer.One common method to achieve pseudomenopause is through the use of hormonal medications, such as gonadotropin-releasing hormone (GnRH) agonists or antagonists. These medications work by suppressing the production of estrogen and progesterone, which are the hormones responsible for regulating the menstrual cycle. By reducing the levels of these hormones, the menstrual cycle can be temporarily halted or significantly reduced.Another approach to induce pseudomenopause is through the removal or destruction of the ovaries. This can be done surgically, through a procedure called oophorectomy, or through radiation therapy. By removing or damaging the ovaries, the production of estrogen and progesterone is permanently halted, resulting in a state similar to menopause.It is important to note that pseudomenopause is a temporary state and the menstrual cycle usually resumes once the medications are discontinued or the effects of the procedure wear off. Additionally, the side effects and risks associated with these treatments should be carefully considered and discussed with a healthcare professional before undergoing any such procedures.
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This question is part of the following fields:
- Obstetrics & Gynaecology
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Question 8
Incorrect
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Which structure carries or comes into contact with oxygenated blood?
Your Answer: Pulmonary artery
Correct Answer: Pulmonary vein
Explanation:The pulmonary veins transport blood that is rich in oxygen, while the pulmonary artery carries blood that lacks oxygen. The right atrium, which includes the crista terminalis and pectinate muscle, and the right ventricle, which contains the septomarginal trabecula, both carry blood that is low in oxygen.
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This question is part of the following fields:
- Anatomy
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Question 9
Correct
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Where is the pain commonly referred from the inflammation of the cystic duct?
Your Answer: Right shoulder
Explanation:The pain commonly referred from the inflammation of the cystic duct is typically felt in the right shoulder. This is known as referred pain, where the pain is felt in a different location than the actual source of the problem. In the case of cystic duct inflammation, the pain is often felt in the right shoulder because the nerves that supply the gallbladder and the shoulder region share a common pathway. This phenomenon is known as referred pain and is a result of the way the nerves are interconnected in the body. The other options listed (epigastric, umbilical, hypogastric) are not typically associated with the inflammation of the cystic duct.
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This question is part of the following fields:
- Surgery
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Question 10
Correct
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A 4-year-old female patient comes to you because the pet dog licked her hand. PE revealed no break in the skin. What is the appropriate management?
Your Answer: Wash exposed skin with soap and water
Explanation:The appropriate management for a 4-year-old female patient who has been licked by a pet dog with no break in the skin is to wash the exposed skin with soap and water. This is because the risk of rabies transmission through a lick without a break in the skin is extremely low. Rabies is typically transmitted through bites or scratches that break the skin and allow the virus to enter the body. Washing the area with soap and water helps to further reduce any potential risk of infection. Vaccination and administration of rabies immune globulin (RIG) are not necessary in this case, as there is no known exposure to the rabies virus. Therefore, the appropriate management in this scenario is to wash the exposed skin with soap and water.
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This question is part of the following fields:
- Preventive Medicine
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Question 11
Incorrect
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Which cranial nerve originates from the diencephalon?
Your Answer: Trigeminal nerve (CN V)
Correct Answer: Optic nerve (CN Il)
Explanation:The cranial nerve Il originates from the diencephalon and serves as a pathway within the central nervous system.
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This question is part of the following fields:
- Embryology
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Question 12
Correct
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During which phase of labor do fetal flexion, rotation, extension, and expulsion occur?
Your Answer: Phase of maximum slope
Explanation:Fetal flexion, rotation, extension, and expulsion occur during the second stage of labor, also known as the phase of maximum slope. This stage begins when the cervix is fully dilated and ends with the birth of the baby. During this phase, the baby’s head starts to descend into the birth canal, and the fetal flexion allows the head to tuck in and fit through the pelvis. As the baby continues to descend, it rotates to align its head with the mother’s pelvis. Once the head is aligned, extension occurs as the baby’s head passes through the birth canal, and finally, expulsion happens when the baby’s head emerges completely. This phase is characterized by strong contractions and intense pushing efforts from the mother.
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This question is part of the following fields:
- Obstetrics & Gynaecology
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Question 13
Correct
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What is the most important intracellular buffer?
Your Answer: Proteins
Explanation:The most important intracellular buffer is proteins. Proteins play a crucial role in maintaining the pH balance within cells. They act as buffers by accepting or donating hydrogen ions (H+) to regulate the acidity or alkalinity of the intracellular environment. This buffering capacity of proteins helps to prevent drastic changes in pH, which is essential for the proper functioning of cellular processes. Additionally, proteins also act as buffers in the extracellular fluid, helping to maintain the overall pH balance of the body. While bicarbonate, carbon dioxide, water, and phosphate also contribute to intracellular buffering, proteins are considered the most important due to their abundance and versatility in buffering capacity.
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This question is part of the following fields:
- Biochemistry
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Question 14
Incorrect
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What is a highly lipophilic derivative of ubiquinone that has activity against Plasmodium species and Pneumocystis pneumonia among patients intolerant to Co-trimoxazole?
Your Answer: Quinine
Correct Answer: Atovaquone
Explanation:The highly lipophilic derivative of ubiquinone is atovaquone which is a hydroxynaphthoquinone with antimicrobial and antipneumocystis activity. It is a lipophilic compound that is able to dissolve in and interact with lipid-based substances, which can be important for their activity in certain biological systems.Plasmodium species are the parasites that cause malaria, a potentially life-threatening disease. Pneumocystis pneumonia, on the other hand, is a type of lung infection that primarily affects individuals with weakened immune systems, such as those with HIV/AIDS.atovaquone is also effective for patients who are intolerant to Co-trimoxazole. Co-trimoxazole is a combination antibiotic commonly used to treat a variety of bacterial and parasitic infections. However, some individuals may experience adverse reactions or intolerance to this medication.Therefore, atovaquone serves as an alternative treatment option for patients who cannot tolerate Co-trimoxazole. Its lipophilic nature may allow it to penetrate lipid-rich environments, such as the cell membranes of plasmodium species or Pneumocystis pneumonia, and exert its therapeutic effects.Overall, this compound represents a potential therapeutic option for individuals who require treatment for plasmodium species or Pneumocystis pneumonia but cannot tolerate Co-trimoxazole. Its lipophilic properties may contribute to its effectiveness in targeting these specific pathogens.
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This question is part of the following fields:
- Pharmacology
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Question 15
Incorrect
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Which of the following is true regarding maternal mortality in the Philippines?
Your Answer: Cervical cancer remains as the second leading cause of maternal mortality
Correct Answer: Hypertension is the leading cause of mortality
Explanation:The Philippine Health Statistics 2000 (PHS) revealed that 25 percent of all maternal deaths are due to hypertension
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This question is part of the following fields:
- Obstetrics & Gynaecology
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Question 16
Incorrect
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Which statement is true regarding competitive inhibition?
Your Answer: Inhibitor binds to allosteric site of the enzyme and halts the enzyme catalysis.
Correct Answer: Reversal of the inhibition is through increasing the substrate.
Explanation:The true statement regarding competitive inhibition is: Reversal of the inhibition is through increasing the substrate.In competitive inhibition, the inhibitor molecule competes with the substrate for binding to the active site of the enzyme. When the inhibitor is bound to the enzyme’s active site, it prevents the substrate from binding and initiating the enzymatic reaction. However, competitive inhibition can be overcome by increasing the concentration of the substrate. When the substrate concentration is increased, it is more likely to outcompete the inhibitor for binding to the enzyme’s active site, leading to the restoration of enzymatic activity.Here’s a brief explanation of the other options:Km is constant: This statement is not true. Competitive inhibition increases the apparent Km value because more substrate is needed to achieve half-maximal velocity (Vmax/2) in the presence of the inhibitor.Inhibitor binds to allosteric site of the enzyme and halts the enzyme catalysis: This statement describes non-competitive inhibition, where the inhibitor binds to an allosteric site on the enzyme rather than the active site.Vmax is lowered: Vmax is unchanged in competitive inhibition, but it is not a defining characteristic. The primary effect is on the apparent Km value.Inhibitor changes the shape of the enzyme so it cannot bind to the substrate: This statement describes irreversible enzyme inhibition, such as irreversible covalent binding of inhibitors, which is different from competitive inhibition, where the inhibitor can dissociate from the enzyme.
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This question is part of the following fields:
- Biochemistry
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Question 17
Incorrect
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A newborn was noted to be cyanotic, unfortunately, the imaging facilities are unavailable for the day. A hyperoxia test was thus done, which showed no improvement of PaO2 after administration of 100% O2. What is the next step in the management of this neonate?
Your Answer: Positive pressure ventilation
Correct Answer: Prostaglandin E
Explanation:The next step in the management of this neonate would be to administer prostaglandin E. Cyanosis in a newborn can be a sign of a congenital heart defect, specifically a duct-dependent lesion. Prostaglandin E is a medication that helps maintain the patency of the ductus arteriosus, which is a blood vessel that connects the pulmonary artery to the aorta in the fetus. In some cases, the ductus arteriosus needs to remain open to allow for adequate blood flow to the body until surgical intervention can be performed.If the hyperoxia test did not improve the newborn’s oxygen levels, it suggests that the cyanosis is not due to a respiratory issue but rather a cardiac issue. Administering prostaglandin E can help maintain blood flow to the body and prevent further deterioration while awaiting further evaluation and possible surgical intervention.
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This question is part of the following fields:
- Paediatrics
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Question 18
Correct
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A 23-year-old female came into your clinic due to a 5-day history of vaginal discharge. On pelvic examination, you noted green-yellow frothy discharge and multiple erythematous punctate lesions in her vagina. With your diagnosis in mind, which of the following regimens would you prescribe to your patient?
Your Answer: Metronidazole 2 g PO single dose
Explanation:The correct answer is A. Metronidazole 2 g PO single dose.The patient’s symptoms and physical examination findings are consistent with a diagnosis of trichomoniasis, which is a sexually transmitted infection caused by the parasite Trichomonas vaginalis. The characteristic green-yellow frothy discharge and erythematous punctate lesions in the vagina are classic signs of trichomoniasis.Metronidazole is the treatment of choice for trichomoniasis. A single dose of 2 g is effective in treating the infection. The alternative regimen of metronidazole 500 mg BID for 7 days is also acceptable.Fluconazole is an antifungal medication used to treat yeast infections, not trichomoniasis. Nystatin is an antifungal medication used to treat fungal infections, and it is not effective against trichomoniasis.Therefore, the most appropriate treatment option for this patient is metronidazole 2 g PO single dose.
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This question is part of the following fields:
- Obstetrics & Gynaecology
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Question 19
Incorrect
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Which of the following is NOT a feature of the genetic code?
Your Answer: The genetic code is conserved throughout evolution.
Correct Answer: It is overlapping.
Explanation:The feature that is NOT a feature of the genetic code is It is overlapping. The genetic code is a set of rules that determines how the sequence of nucleotides in DNA or RNA is translated into the sequence of amino acids in a protein. Each codon, which consists of three nucleotides, specifies a particular amino acid or a stop signal. The first statement, Each codon specifies only 1 amino acid, is a feature of the genetic code. Each codon is specific to one amino acid, meaning that there is no ambiguity in the translation process. The second statement, Tryptophan and methionine is encoded by only 1 codon, is also a feature of the genetic code. These two amino acids are indeed encoded by a single codon each. For example, the codon AUG specifically codes for methionine, while the codon UGG specifically codes for tryptophan. The third statement, The genetic code is conserved throughout evolution, is another feature of the genetic code. The code is nearly universal, meaning that the same codons specify the same amino acids across different organisms and throughout evolutionary history. This conservation is crucial for the proper functioning of proteins and the transfer of genetic information. However, the statement It is overlapping is not a feature of the genetic code. The genetic code is non-overlapping, meaning that each codon is read separately and does not overlap with the adjacent codons. In other words, the nucleotide sequence is read in a continuous, non-overlapping manner to produce the corresponding amino acid sequence.
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This question is part of the following fields:
- Biochemistry
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Question 20
Correct
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What is the backbone structure of sphingomyelin, an important constituent of the myelin sheath of nerves?
Your Answer: Sphingosine
Explanation:The backbone structure of sphingomyelin, an important constituent of the myelin sheath of nerves, is sphingosine. Sphingosine is a long-chain amino alcohol that forms the core structure of sphingomyelin. It consists of a long hydrocarbon chain with a terminal amino group and a hydroxyl group. This backbone structure provides stability and rigidity to the sphingomyelin molecule.Sphingosine is attached to a fatty acid through an amide bond. The fatty acid, such as palmitic acid, forms the acyl chain of sphingomyelin. This fatty acid component contributes to the hydrophobic nature of sphingomyelin, allowing it to interact with the lipid bilayer of the myelin sheath.In addition to the sphingosine and fatty acid components, sphingomyelin also contains a polar head group. This head group can vary and may include an oligosaccharide or N-acetyl neuraminic acid. These polar head groups are located on the opposite end of the sphingosine backbone from the fatty acid. They contribute to the overall charge and hydrophilicity of sphingomyelin, allowing it to interact with other molecules and participate in cell signaling processes.Overall, the backbone structure of sphingomyelin consists of sphingosine, which is attached to a fatty acid and may have a polar head group. This unique structure is essential for the function of sphingomyelin in the myelin sheath, where it provides insulation and support to nerve fibers.
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This question is part of the following fields:
- Biochemistry
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Question 21
Incorrect
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A 24-year-old woman who receives a deep cut to her ring finger by a kitchen knife is unable to move the metacarpophalangeal joint. Which of the following pairs of nerves was damaged?
Your Answer: Median and ulnar
Correct Answer: Ulnar and radial
Explanation:The ulnar nerve controls the muscles that flex the metacarpophalangeal joint of the ring finger, including the lumbrical, palmar, and dorsal interosseous muscles. On the other hand, the radial nerve innervates the extensor digitorum muscle, which extends this joint. The musculocutaneous and axillary nerves do not provide innervation to hand muscles. Lastly, the median nerve controls the lateral two lumbricals, allowing them to flex the metacarpophalangeal joints of the index and middle fingers.
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This question is part of the following fields:
- Anatomy
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Question 22
Correct
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Why is lymph moved through lymphatic vessels?
Your Answer: Skeletal Muscle contraction
Explanation:Lymph is moved through lymphatic vessels primarily due to skeletal muscle contraction. Unlike blood, lymph does not have a central pump like the heart to propel it through the vessels. Instead, the movement of lymph is facilitated by the contraction of skeletal muscles surrounding the lymphatic vessels. When these muscles contract, they squeeze the lymphatic vessels, pushing the lymph forward. This movement is similar to how squeezing a tube of toothpaste pushes the toothpaste out of the tube. Additionally, the presence of valves within the lymphatic vessels helps to prevent backflow and ensure the one-way flow of lymph towards the heart.
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This question is part of the following fields:
- Physiology
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Question 23
Incorrect
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True of heart sounds:
Your Answer: AV valves are more taut than semilunar valves.
Correct Answer: S1 is caused by closure of the aortic valve
Explanation:The statement S2 is slightly longer in duration than S1 is true. S1, also known as the first heart sound, is caused by the closure of the mitral and tricuspid valves, which occurs at the beginning of ventricular systole. This sound is relatively short in duration. On the other hand, S2, also known as the second heart sound, is caused by the closure of the aortic and pulmonary valves, which occurs at the beginning of ventricular diastole. This sound is slightly longer in duration compared to S1.The statement S2 has a lower frequency than S1 is false. The frequency of a sound refers to the number of cycles or vibrations per unit of time. In the case of heart sounds, the frequency is determined by the rate at which the valves close. S1 has a higher frequency than S2 because it is caused by the closure of the mitral and tricuspid valves, which occurs earlier in the cardiac cycle compared to the closure of the aortic and pulmonary valves that cause S2.The statement S1 is caused by closure of the aortic valve is false. S1 is actually caused by the closure of the mitral and tricuspid valves, which are the atrioventricular (AV) valves. The closure of these valves marks the beginning of ventricular systole and the onset of the first heart sound.The statement S2 is caused by oscillation of blood between walls of ventricles is false. S2 is caused by the closure of the aortic and pulmonary valves, which are the semilunar valves. These valves prevent the backflow of blood from the aorta and pulmonary artery into the ventricles during ventricular diastole. The closure of these valves produces the second heart sound.The statement AV valves are more taut than semilunar valves is false. The AV valves, including the mitral and tricuspid valves, are actually more flexible and less taut compared to the semilunar valves, including the aortic and pulmonary valves. This flexibility allows the AV valves to open and close in response to changes in pressure within the heart chambers, facilitating the flow of blood in the correct direction. The semilunar valves, on the other hand, are more rigid and taut, ensuring the prevention of backflow of blood.
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This question is part of the following fields:
- Physiology
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Question 24
Correct
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A 3-year-old is brought to the ER. On PE, inspiratory stridor and a barking cough were noted. There is mild respiratory distress, tachypnea, and fever. The signs and symptoms are aggravated by agitation and crying. What is the most likely diagnosis?
Your Answer: Laryngotracheobronchitis
Explanation:The most likely diagnosis in this case is Laryngotracheobronchitis, also known as croup. Croup is a viral infection that causes inflammation of the upper airway, including the larynx and trachea. It is most commonly seen in children between the ages of 6 months and 3 years.The symptoms described in the question are classic for croup. Inspiratory stridor, a barking cough, and mild respiratory distress are all characteristic findings. The stridor is caused by the narrowing of the airway due to inflammation, and it is typically worse during inspiration. The barking cough is a result of the inflammation and swelling of the vocal cords.Fever is also commonly seen in croup, although it is usually mild. The signs and symptoms of croup are often aggravated by agitation and crying, as these activities can further narrow the already inflamed airway.Tracheomalacia, or weakness of the tracheal cartilage, is a possible differential diagnosis. However, it is less likely in this case because the symptoms described are consistent with an acute viral infection rather than a chronic condition.Epiglottitis is another possible differential diagnosis. However, it is less likely in this case because the symptoms of epiglottitis typically progress rapidly and can be life-threatening. The patient in this case has mild respiratory distress and the symptoms are not described as rapidly worsening.Bacterial tracheitis and peritonsillar abscess are less likely diagnoses in this case because they typically present with more severe symptoms, such as high fever, severe respiratory distress, and drooling.
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This question is part of the following fields:
- Paediatrics
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Question 25
Correct
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Which of the following drugs have a direct toxic effect on hepatocytes?
Your Answer: All of the options given
Explanation:Drugs that have a direct toxic effect on hepatocytes are those that can cause damage or injury to liver cells. These drugs can lead to hepatotoxicity, which is the term used to describe liver damage caused by medications.Some examples of drugs that have a direct toxic effect on hepatocytes include:1. Acetaminophen (paracetamol): When taken in excessive amounts or in combination with alcohol, acetaminophen can cause liver damage. It is one of the most common causes of drug-induced liver injury.2. Nonsteroidal anti-inflammatory drugs (NSAIDs): Certain NSAIDs, such as diclofenac and ibuprofen, have been associated with hepatotoxicity. Prolonged use or high doses of these drugs can lead to liver damage.3. Statins: These cholesterol-lowering medications, including atorvastatin and simvastatin, can rarely cause liver damage. Regular monitoring of liver function is recommended for patients taking statins.4. Methotrexate: This medication is commonly used to treat cancer, rheumatoid arthritis, and psoriasis. However, it can cause liver toxicity, especially at higher doses or with long-term use.5. Isoniazid: This drug is used to treat tuberculosis. It can cause liver damage, particularly in individuals with pre-existing liver disease or those who consume alcohol regularly.6. Amiodarone: This antiarrhythmic medication can cause liver toxicity in some patients. Regular liver function tests are necessary for individuals taking amiodarone.It is important to note that the toxic effects of these drugs on hepatocytes can vary among individuals. Some people may be more susceptible to liver damage due to genetic factors or pre-existing liver conditions. Regular monitoring of liver function and following the prescribed dosage and duration of these medications can help minimize the risk of hepatotoxicity.
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This question is part of the following fields:
- Internal Medicine
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Question 26
Incorrect
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What is the measure of the rate of dissemination of an epidemic?
Your Answer: Prevalence rate
Correct Answer: Generation time
Explanation:The generation time is the measure of the rate of dissemination of an epidemic. It is the average time it takes for a susceptible person to become infected after being exposed to an infected person.The pre-patent period is the time from infection to when the person can first transmit the infection to others.The prevalence rate is the number of people infected with a disease at a particular time in a population.The incubation period is the time from infection to when the person first develops symptoms.The attack rate is the proportion of people in a population who are infected with a disease during an epidemic.
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This question is part of the following fields:
- Preventive Medicine
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Question 27
Incorrect
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An 8-month-old manifests with fussiness and emesis and refuses to eat. One week ago, he was brought for a consult and was diagnosed with URTI. On the morning of the consult, his mother noted currant jelly-like material on his diaper. On PE, a sausage-shaped mass was palpable in the abdomen. There is likewise abdominal distention, and rectal exam reveals blood in the stool. What is the most likely diagnosis?
Your Answer: Hypertrophic pyloric stenosis
Correct Answer: Intussusception
Explanation:The most likely diagnosis in this case is intussusception. Intussusception occurs when one segment of the intestine telescopes into another segment, causing a blockage. This can lead to symptoms such as abdominal pain, vomiting, and bloody stools. The presence of a sausage-shaped mass in the abdomen and blood in the stool are both consistent with intussusception. The currant jelly-like material on the diaper is also a characteristic finding, as it represents a mixture of blood and mucus. Duodenal atresia, hypertrophic pyloric stenosis, and intestinal adenoma are all possible causes of gastrointestinal symptoms in infants, but they do not typically present with the specific findings seen in this case. Viral diarrhea is a common cause of gastrointestinal symptoms in children, but it does not typically cause the physical exam findings seen in this case.
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This question is part of the following fields:
- Paediatrics
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Question 28
Incorrect
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A 12-year-old boy was eating hurriedly when the school bell rang, which signaled the end of the recess period. He suddenly choked while swallowing the siomai whole without chewing. The Heimlich maneuver was done but was unsuccessful in dislodging the food from the airways. A rigid bronchoscopy was performed. Where is the siomai most likely lodged?
Your Answer: Posterior basal bronchopulmonary segment of the right inferior lobe
Correct Answer: Posterior bronchopulmonary segment of the right superior lobe
Explanation:The siomai is most likely lodged in the posterior bronchopulmonary segment of the right superior lobe. The Heimlich maneuver is a technique used to dislodge an obstruction from the airway by applying pressure to the abdomen. In this case, it was unsuccessful in removing the siomai from the airway. A rigid bronchoscopy is a procedure in which a rigid tube is inserted into the airway to visualize and remove foreign objects or obstructions. The fact that a rigid bronchoscopy was performed suggests that the siomai could not be dislodged using less invasive methods. The specific location of the siomai is most likely in the posterior bronchopulmonary segment of the right superior lobe. This is because the siomai was swallowed whole without chewing, and the right superior lobe is more likely to be the site of lodgment due to the anatomy of the airway.
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This question is part of the following fields:
- Anatomy
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Question 29
Correct
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Bile acids are synthesized from cholesterol. Which of the following is an example of primary bile acids?
Your Answer: Chenodeoxycholic acid
Explanation:Primary bile acids are synthesized in the liver from cholesterol. Cholic acid and chenodeoxycholic acid are the primary bile acids in humans. Cholic acid is produced in the liver and then conjugated with the amino acid glycine or taurine to form glycocholic acid or taurocholic acid, respectively. These primary bile acids are then released into the bile and stored in the gallbladder. When needed, they are released into the small intestine to aid in the digestion and absorption of dietary fats.
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This question is part of the following fields:
- Biochemistry
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Question 30
Incorrect
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What enzyme is deficient in Gaucher disease?
Your Answer: Alpha-galactosidase
Correct Answer: Glucocerebrosidase
Explanation:The enzyme that is deficient in Gaucher disease is glucocerebrosidase. Gaucher disease is a rare genetic disorder characterized by the accumulation of a fatty substance called glucocerebroside in certain organs and tissues, particularly the liver, spleen, and bone marrow. Glucocerebrosidase is responsible for breaking down glucocerebroside into glucose and ceramide, but in individuals with Gaucher disease, there is a deficiency or absence of this enzyme. As a result, glucocerebroside builds up in the cells, leading to the symptoms and complications associated with Gaucher disease.
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This question is part of the following fields:
- Paediatrics
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Question 31
Incorrect
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Which of the following statements regarding bacterial toxins is/are incorrect?
Your Answer: Exotoxins are found both in Gram positive and Gram negative bacteria
Correct Answer: All exotoxins are heat labile and are rapidly inactivated by heating above 60 °C
Explanation:Exotoxins are found both in Gram positive and Gram negative bacteria: This statement is correct. Exotoxins can be produced by both Gram-positive and Gram-negative bacteria.All exotoxins are heat labile and are rapidly inactivated by heating above 60 °C: This is is incorrect. Not all exotoxins are heat labile. Some exotoxins, such as tetanus toxin, are heat stable and can survive boiling.The lipid A component of LPS is probably responsible for its toxicity: This statement is correct. The lipid A component of lipopolysaccharides (LPS) in Gram-negative bacteria is responsible for the endotoxic properties of LPS.Exotoxins bind to specific cell receptors while endotoxins do not: This statement is correct. Exotoxins do bind to specific cell receptors, allowing them to enter and exert their effects on host cells. On the other hand, endotoxins, specifically referring to the lipid A portion of LPS, do not bind to specific cell receptors; they activate innate immune responses through interactions with pattern recognition receptors.
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This question is part of the following fields:
- Microbiology
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Question 32
Correct
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What is the mechanism of action of the enterotoxin secreted by Staphylococcus in a burn patient with toxic shock syndrome?
Your Answer: Inducing the secretion of high concentrations of cytokines
Explanation:The superantigen made by Staphylococcus binds both the T cell receptor and the MHC class II molecule at the same time, regardless of the specific antigen present. This interaction between a cell presenting the antigen and a T cell causes a widespread activation of effector cells, leading to a significant release of cytokines, commonly known as a Cytokine Storm.
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This question is part of the following fields:
- Microbiology
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Question 33
Incorrect
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A 25-year-old male, who is fond of eating undercooked crabs and has poor hygiene, has a 3-week history of chronic cough with bloody sputum. What is the most likely diagnosis?
Your Answer: Loeffler's pneumonia
Correct Answer: Paragonimiasis
Explanation:The most likely diagnosis in this case is Paragonimiasis. Paragonimiasis is a parasitic infection caused by the lung fluke Paragonimus. It is commonly acquired by consuming undercooked or raw crustaceans, such as crabs or crayfish, which are the intermediate hosts for the parasite. The poor hygiene of the individual increases the risk of infection.The symptoms of Paragonimiasis include chronic cough, which can be accompanied by bloody sputum. Other common symptoms include chest pain, difficulty breathing, and fever. These symptoms can persist for weeks or even months if left untreated.Histoplasmosis is a fungal infection caused by inhaling spores of the fungus Histoplasma capsulatum. It typically presents with flu-like symptoms and can cause lung problems, but it is not associated with eating undercooked crabs.Tuberculosis is a bacterial infection caused by Mycobacterium tuberculosis. It can cause chronic cough with bloody sputum, but it is not related to eating undercooked crabs.Loeffler’s pneumonia is a rare condition characterized by eosinophilic pneumonia. It is usually caused by parasitic infections or allergic reactions. While it can cause cough and sputum production, it is not specifically associated with eating undercooked crabs.Bronchiectasis is a chronic condition characterized by the permanent dilation of the bronchi. It can cause chronic cough and sputum production, but it is not related to eating undercooked crabs.
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This question is part of the following fields:
- Microbiology
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Question 34
Incorrect
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A 6-month-old child was noted to have slow weight gain and mild delay in achieving developmental milestones. One morning, the parents noted that their child seems unable to move the right side of his body. Which condition could explain this child's presentation?
Your Answer: Maple syrup disease
Correct Answer: Hemiplegia
Explanation:The condition that could explain this child’s presentation is hemiplegia, which is a paralysis or weakness affecting one side of the body. Hemiplegia can be caused by various factors, including stroke, brain injury, or a neurological disorder. In this case, the sudden inability to move the right side of the body suggests a neurological issue. The slow weight gain and mild delay in achieving developmental milestones also indicate a possible underlying neurological condition. Therefore, the most likely explanation for this child’s presentation is a neurological disorder rather than metabolic disorders like phenylketonuria, cystathioninuria, homocystinuria, or maple syrup disease.
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This question is part of the following fields:
- Biochemistry
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Question 35
Correct
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A 60-year-old male was diagnosed with refractory follicular B-cell lymphoma. He was prescribed with an agent that binds CD20 on both normal and malignant B lymphocytes. Which of the following is this drug?
Your Answer: Rituximab
Explanation:The drug that binds CD20 on both normal and malignant B lymphocytes is Rituximab. Rituximab is a monoclonal antibody that specifically targets CD20, a protein found on the surface of B cells. By binding to CD20, Rituximab helps to destroy both normal and malignant B cells, making it an effective treatment for B-cell lymphomas such as follicular B-cell lymphoma. Cetuximab, Bevacizumab, Omalizumab, and Natalizumab are all different drugs that target different proteins and are used for different medical conditions.
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This question is part of the following fields:
- Pharmacology
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Question 36
Incorrect
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Which of the following is not a risk factor for osteoporosis?
Your Answer: Injury
Correct Answer: Obesity
Explanation:The answer to this question is Obesity. Obesity is not a risk factor for osteoporosis. In fact, having a higher body weight can actually be protective against osteoporosis because the extra weight puts more stress on the bones, which can stimulate bone growth and increase bone density. On the other hand, the other options listed are all risk factors for osteoporosis. Family history plays a role in determining a person’s risk of developing osteoporosis, as genetics can influence bone density. S/p TAHBSO (surgical removal of the uterus and ovaries) can lead to a decrease in estrogen levels, which can accelerate bone loss. Injury, especially fractures, can indicate weakened bones and may be a sign of osteoporosis. Lastly, age is a significant risk factor for osteoporosis, as bone density naturally decreases as we get older.
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This question is part of the following fields:
- Internal Medicine
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Question 37
Correct
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Which enzyme in the steroid hormone synthetic pathway needs to be inhibited in order to decrease the size of the prostate?
Your Answer: 5α-Reductase
Explanation:The enzyme 5α-Reductase helps convert testosterone into dihydrotestosterone, which is the main active hormone in certain male reproductive tissues like the prostate.
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This question is part of the following fields:
- Physiology
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Question 38
Incorrect
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Which of the following vasodilators are not vasodilators?
Your Answer: Nitric oxide
Correct Answer: None of the options given
Explanation:The correct answer is None of the above. All of the options listed – Serotonin, Prostacyclin, Nitric oxide, and Histamine – are vasodilators. Vasodilators are substances that cause the blood vessels to relax and widen, leading to an increase in blood flow. Serotonin, Prostacyclin, Nitric oxide, and Histamine all have the ability to dilate blood vessels and promote blood flow to various tissues and organs in the body.
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This question is part of the following fields:
- Physiology
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Question 39
Correct
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What is the tissue form of candidiasis?
Your Answer: Yeast cells with multiple narrow based bud
Explanation:The tissue form of candidiasis is characterized by yeast cells with multiple narrow based buds. Candidiasis is a fungal infection caused by the overgrowth of Candida species, particularly Candida albicans. In the tissue form of candidiasis, the yeast cells invade and multiply within the tissues, leading to inflammation and damage. The yeast cells are typically seen with multiple narrow based buds, which are small projections that form on the surface of the yeast cell. This characteristic appearance helps in the identification of Candida species under a microscope.
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This question is part of the following fields:
- Microbiology
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Question 40
Incorrect
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An infant suffers from loose water stools with vomiting and fever episodes. Which statement is true regarding the most likely organism?
Your Answer: It is an enveloped organism.
Correct Answer: It belongs to family Reoviridae.
Explanation:The most likely organism in this case is a virus belonging to the family Reoviridae. This is because the symptoms described, including loose water stools, vomiting, and fever, are characteristic of a viral infection. The statement It can be easily cultured is not necessarily true for all viruses, as some viruses are more difficult to culture in a laboratory setting. The statement It is an enveloped organism is not applicable to viruses in the family Reoviridae, as they are non-enveloped viruses. The statement Its genetic component is single-stranded is also not applicable to viruses in the family Reoviridae, as they have a double-stranded RNA genome. Therefore, the correct statement is It belongs to family Reoviridae.
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This question is part of the following fields:
- Microbiology
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Question 41
Incorrect
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A 56-year-old hypertensive and diabetic male complained of chest pains and was brought to the emergency room. ECG showed ST segment elevation, and lab work-up showed elevated troponin and CK-MB. What type of necrosis is expected in the cardiac muscle?
Your Answer: Liquefactive
Correct Answer: Coagulation
Explanation:The type of necrosis expected in the cardiac muscle of this patient is coagulative necrosis. Coagulative necrosis is a type of cell death that occurs due to ischemia, which is the inadequate blood supply to the tissues. In this case, the patient’s chest pains and the ECG findings of ST segment elevation suggest that he may be experiencing a myocardial infarction, commonly known as a heart attack.During a heart attack, the blood supply to a part of the heart muscle is blocked, usually due to a blood clot in one of the coronary arteries. This blockage leads to ischemia and subsequent cell death. Coagulative necrosis occurs in the cardiac muscle because the lack of blood supply prevents the delivery of oxygen and nutrients to the cells, leading to their death.The elevated troponin and CK-MB levels in the lab work-up further support the diagnosis of a myocardial infarction. Troponin is a protein released into the bloodstream when there is damage to the heart muscle, and CK-MB is an enzyme that is released when there is damage to the cardiac muscle cells. The elevation of these markers indicates that there has been injury to the heart muscle, confirming the diagnosis of a heart attack.In summary, the combination of chest pains, ST segment elevation on ECG, and elevated troponin and CK-MB levels suggest that the patient is experiencing a myocardial infarction, which would result in coagulative necrosis in the cardiac muscle.
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This question is part of the following fields:
- Pathology
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Question 42
Incorrect
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What are the stigmata of liver cirrhosis, excluding all of the following?
Your Answer: Spider angiomata
Correct Answer: None of the options given
Explanation:The stigmata of liver cirrhosis are physical signs or symptoms that are commonly associated with this condition. In this case, we are asked to exclude testicular atrophy, spider angiomata, gynecomastia, and esophageal varices from the list of stigmata.Testicular atrophy refers to the shrinking of the testicles, which can occur in liver cirrhosis due to hormonal imbalances. Spider angiomata are small, dilated blood vessels that appear on the skin, often in a spider-like pattern. Gynecomastia is the enlargement of breast tissue in males, which can also be caused by hormonal changes in liver cirrhosis. Esophageal varices are enlarged veins in the lower part of the esophagus, which can be a complication of liver cirrhosis.Therefore, the correct answer is None of the above since all of the listed options (testicular atrophy, spider angiomata, gynecomastia, and esophageal varices) are indeed stigmata of liver cirrhosis.
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This question is part of the following fields:
- Internal Medicine
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Question 43
Incorrect
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What is a fusion inhibitor used in the treatment of HIV infection?
Your Answer: Lamivudine
Correct Answer: Enfuvirtide
Explanation:A fusion inhibitor used in the treatment of HIV infection is Enfuvirtide. Enfuvirtide belongs to a class of antiretroviral drugs called entry inhibitors. It works by blocking the fusion of the HIV virus with the host cell, preventing the virus from entering and infecting the cell. By inhibiting this step in the viral replication cycle, Enfuvirtide helps to reduce the viral load in HIV-infected individuals and slow down the progression of the disease. Enfuvirtide is typically used in combination with other antiretroviral drugs as part of a highly active antiretroviral therapy (HAART) regimen.
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This question is part of the following fields:
- Pharmacology
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Question 44
Incorrect
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In which part of the uterus is the incision made for a low transverse cesarean section?
Your Answer: Body
Correct Answer: Lower uterine segment
Explanation:The incision for a low transverse cesarean section is made in the lower uterine segment of the uterus. This is the area located just above the cervix. The lower uterine segment is chosen for the incision because it is thinner and less vascular than the upper part of the uterus, known as the fundus. Making the incision in the lower uterine segment reduces the risk of bleeding and complications during the surgery. Additionally, this type of incision allows for a more favorable healing process and a lower risk of uterine rupture in future pregnancies.
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This question is part of the following fields:
- Obstetrics & Gynaecology
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Question 45
Incorrect
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Which of the following is not an immune complex-mediated disease?
Your Answer: None of the options given
Correct Answer: Multiple sclerosis
Explanation:The correct answer is Multiple sclerosis. Multiple sclerosis is not an immune complex-mediated disease. Systemic Lupus Erythematosus, Polyarteritis nodosa, and Poststreptococcal glomerulonephritis are all examples of immune complex-mediated diseases. In these diseases, the immune system produces antibodies that form immune complexes with antigens. These immune complexes can then deposit in various tissues and organs, leading to inflammation and tissue damage.Systemic Lupus Erythematosus is a chronic autoimmune disease that can affect multiple organs and tissues, including the skin, joints, kidneys, heart, and lungs. It is characterized by the presence of autoantibodies, such as anti-nuclear antibodies, which form immune complexes with self-antigens.Polyarteritis nodosa is a rare autoimmune disease that affects the medium-sized arteries, leading to inflammation and damage to various organs, including the skin, nerves, kidneys, and gastrointestinal tract. Immune complexes play a role in the pathogenesis of this disease.Poststreptococcal glomerulonephritis is a type of kidney disease that occurs after an infection with certain strains of streptococcus bacteria. Immune complexes formed in response to the infection can deposit in the glomeruli of the kidneys, leading to inflammation and impaired kidney function.On the other hand, Multiple sclerosis is a chronic neurological disease that is characterized by the immune system mistakenly attacks the myelin sheath, a protective covering of nerve fibers in the central nervous system. It is not considered an immune complex-mediated disease because it does not involve the formation and deposition of immune complexes. Instead, it is primarily a T-cell-mediated autoimmune disease.
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This question is part of the following fields:
- Pathology
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Question 46
Incorrect
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What is the causative agent of granulomatosis infantiseptica?
Your Answer: Streptococcus agalactiae
Correct Answer: Listeria monocytogenes
Explanation:The causative agent of granulomatosis infantiseptica is Listeria monocytogenes. Granulomatosis infantiseptica is a rare and severe form of listeriosis, which is an infection caused by the bacterium Listeria monocytogenes. This bacterium is commonly found in soil, water, and some animals, and can be transmitted to humans through contaminated food, particularly unpasteurized dairy products, raw vegetables, and processed meats. In infants, the infection can occur during pregnancy if the mother is infected, or after birth through contaminated breast milk or contact with infected individuals or objects. Granulomatosis infantiseptica is characterized by the formation of granulomas, which are small areas of inflamed tissue, throughout the body, including the liver, spleen, lungs, and brain. It can lead to severe complications and even death, particularly in newborns and individuals with weakened immune systems. Prompt diagnosis and treatment with antibiotics are crucial in managing this condition.
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This question is part of the following fields:
- Microbiology
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Question 47
Incorrect
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Which of the following actions have been proven to decrease mortality and morbidity from measles infection?
Your Answer: Vitamin D supplementation
Correct Answer: Vitamin A supplementation
Explanation:The action that has been proven to decrease mortality and morbidity from measles infection is Vitamin A supplementation. Vitamin A deficiency is known to increase the severity of measles infection and can lead to complications such as pneumonia and blindness. Supplementing with Vitamin A has been shown to reduce the risk of these complications and improve outcomes in individuals with measles. The other supplements mentioned (zinc, Vitamin D, Vitamin C, and iron) may have various health benefits, but they have not been specifically proven to decrease mortality and morbidity from measles infection.
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This question is part of the following fields:
- Preventive Medicine
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Question 48
Correct
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Patient was aware that the physician was drinking, yet he allowed the doctor to inject him. Which doctrine is applicable?
Your Answer: Res ipsa Loquitur
Explanation:The doctrine that is applicable in this scenario is Captain of the ship. This doctrine holds that the physician is ultimately responsible for the actions and decisions made during a medical procedure, even if the patient is aware of any potential negligence or misconduct on the part of the physician. In this case, the patient was aware that the physician was drinking, but still allowed the doctor to inject him. Despite the patient’s awareness, the physician is still held accountable for any harm caused during the procedure.
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This question is part of the following fields:
- Legal Medicine And Juris
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Question 49
Incorrect
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How should a patient with cervical cancer be managed at this stage, considering the findings of hydronephrosis in the intravenous pyelogram study?
Your Answer: Extrafascial hysterectomy
Correct Answer: TAHBSO + chemoradiation
Explanation:A patient with cervical cancer and findings of hydronephrosis in the intravenous pyelogram study should be managed with TAHBSO (Total Abdominal Hysterectomy and Bilateral Salpingo-Oophorectomy) + chemoradiation.Cervical cancer is a type of cancer that starts in the cervix, the lower part of the uterus. Hydronephrosis refers to the swelling of the kidneys due to a build-up of urine caused by an obstruction in the urinary tract. In this case, the hydronephrosis indicates that the cervical cancer has spread and is causing a blockage in the urinary tract, leading to the swelling of the kidneys.TAHBSO is a surgical procedure that involves the removal of the uterus, cervix, fallopian tubes, and ovaries. It is the standard treatment for early-stage cervical cancer. By removing the uterus and cervix, the primary source of the cancer is eliminated. Additionally, removing the fallopian tubes and ovaries helps to prevent the spread of the cancer to these organs.Chemoradiation is a combination of chemotherapy and radiation therapy. It is commonly used in the treatment of advanced-stage cervical cancer. Chemotherapy uses drugs to kill cancer cells throughout the body, while radiation therapy uses high-energy beams to target and destroy cancer cells in a specific area. By combining these two treatment modalities, the chances of killing cancer cells and preventing their spread are increased.In this case, the presence of hydronephrosis indicates that the cancer has spread and is causing a blockage in the urinary tract. Therefore, a more aggressive treatment approach is required. TAHBSO + chemoradiation is the most appropriate management strategy as it addresses both the primary source of the cancer and the spread to the urinary tract. This combination of surgery and chemotherapy/radiation therapy offers the best chance of controlling the cancer and improving the patient’s prognosis.
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This question is part of the following fields:
- Obstetrics & Gynaecology
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Question 50
Incorrect
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Which of the following statements about the Greater pelvis is false?
Your Answer: Obstetric significance
Correct Answer: Lies above the linea terminalis
Explanation:The statement Lies above the linea terminalis is false. The linea terminalis is a bony ridge that separates the true pelvis from the false pelvis. The greater pelvis, also known as the false pelvis, is located above the linea terminalis and is not involved in the process of childbirth. It is the portion of the pelvis that lies above the pelvic brim and is primarily involved in supporting the abdominal organs.
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This question is part of the following fields:
- Anatomy
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